Ask Question
23 August, 22:14

Two identical charges, 2.0m apart, exert forces of magnitude 4.0N on each other. The value of either charge is : (ke = 9*10^9 N. M^2. C^-2)

+5
Answers (1)
  1. 23 August, 22:21
    0
    4.216 * 10^ (-5) C

    Explanation:

    Parameters given:

    Electrostatic force between charges, F = 4N

    Distance between the charges, r = 2 m

    The electrostatic force acting between two charged particles, q1 and q2, separated by a distance, r, is given as:

    F = (k * q1 * q2) / r²

    Where k = Coulombs constant.

    Since q1 = q2 = q,

    F = (k * q²) / r²

    Inputting all the values:

    4 = (9 * 10^9 * q²) / 2²

    => 16 = (9 * 10^9 * q²)

    => q² = 16 / (9 * 10^9)

    q² = 1.78 * 10^ (-9)

    => q = 4.216 * 10^ (-5) C

    The value of both charges is 4.216 * 10^ (-5) C.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Two identical charges, 2.0m apart, exert forces of magnitude 4.0N on each other. The value of either charge is : (ke = 9*10^9 N. M^2. C^-2) ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers