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31 March, 06:09

Two slits 0.200 mm apart. Light of wavelength 488 nm impinges on the slits and the interference pattern is observed on a surface 1.00 m from the slits. How far from the central axis is the fourth maxima? (9.8 mm)

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  1. 31 March, 06:29
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    distance between two slits d =.2 x 10⁻³ m = 2 x 10⁻⁴

    Distance of screen D = 1.00 m

    wave length of light λ = 488 x 10⁻⁹ m

    distance of fourth maxima

    = 4 x λ D / d

    = 4 x 488 x 10⁻⁹ x 1 / 2 x 10⁻⁴

    = 976 x 10⁻⁵ m.

    = 9.76 x 10⁻³ m

    = 9.8 mm.
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