A baseball (m = 145 g) approaches a bat horizontally at a speed of 36.0 m/s (80.5 mi/h) and is hit straight back at a speed of 47.8 m/s (107 mi/h). If the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the bat, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.

Question

Sweetums

Physics

16 October, 23:46

A baseball (m = 145 g) approaches a bat horizontally at a speed of 36.0 m/s (80.5 mi/h) and is hit straight back at a speed of 47.8 m/s (107 mi/h). If the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the bat, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.

+2

Answers (1)

Know the Answer?

Jaylen Hensley · Answer 1

F = 11046 N

Explanation:

given,

mass of the baseball (m) = 145 g = 0.145 Kg

horizontal speed (u) = - 36 m/s

ball hit is straight back (v) = 47.8 m/s

time of contact = ?

using formula of impulse

Impulse = change in momentum

I = m v - m u

I = 0.145 x (47.8 - (-36))

I = 0.145 x (83.8)

I = 12.151 kg. m/s

we also know

I = F x t

now,

F x t = 12.151 kg. m/s

F x 1.1 ms = 12.151

F = 11046 N