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26 July, 20:10

A person gets into an elevator at the lobby level of a hotel together with his 28-kg suitcase, and gets out at the 10th floor 35 m above. Determine the amount of energy consumed by the motor of the elevator that is now stored in the suitcase. Assume that the vibrational effects in the elevator are negligible.

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  1. 26 July, 20:18
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    P. E = 9604J = 9.60KJ

    Therefore, the amount of energy consumed by the motor of the elevator that is now stored in the suitcase is 9604J

    Explanation:

    The amount of energy consumed by the motor of the elevator that is now stored in the suitcase is equal to the potential energy gained by the suitcase.

    Potential energy is the energy by virtue of its position. And can be written as;

    P. E = mgh

    Given

    mass m = 28kg

    height h = 35m

    Acceleration due to gravity g = 9.8m/s^2

    P. E = 28 * 35 * 9.8

    P. E = 9604J = 9.60KJ

    Therefore, the amount of energy consumed by the motor of the elevator that is now stored in the suitcase is 9604J
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