A cylinder which is in a horizontal position contains an unknown noble gas at 54700 Pa 54700 Pa and is sealed with a massless piston. The piston is slowly, isobarically moved inward 0.150 m 0.150 m, while 16800 J 16800 J of heat is removed from the gas. If the piston has a radius of 0.272 m 0.272 m, calculate the change in internal energy Δ U ΔU of the system.

-14892.93 J

Explanation:

given,

Pressure, P = 54700 Pa

heat removed, Q = 16800 J

radius, r = 0.272 m

distance, d = 0.150 m

internal energy ΔU of the system = ?

We know,

Force = Pressure x area

F = P x A

F = 54700 x π x r²

F = 54700 x π x 0.272²

F = 12713.79 N

Work done = F. d

W = 12713.79 x 0.15

W = 1907.07 J

Change in internal energy ΔU is

ΔU = W + Q

= 1907.07 + (-16800)

= - 14892.93 J

Hence, the change in internal energy is equal to - 14892.93 J