A young boy of mass m = 25 kg sits on a coiled spring that has been compressed to a length 0.4 m shorter than its uncompressed length and then held at this length. Suddenly the spring is released, and the boy flies vertically into the air. He reaches a maximum distance 0.5 m above his initial position. The spring is ideal and massless and we ignore the air friction.

What is the spring constant k of the spring?

What is the speed of the boy when he is 0.4 meters above his starting position?

Question

Jaydon Cabrera

Physics

16 February, 04:56

A young boy of mass m = 25 kg sits on a coiled spring that has been compressed to a length 0.4 m shorter than its uncompressed length and then held at this length. Suddenly the spring is released, and the boy flies vertically into the air. He reaches a maximum distance 0.5 m above his initial position. The spring is ideal and massless and we ignore the air friction.

What is the spring constant k of the spring?

What is the speed of the boy when he is 0.4 meters above his starting position?

+4

Answers (1)

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Mahoney · Answer 1

The spring's elastic potential energy is converted into elastic potential energy of the boy.

Potential energy = elastic energy

mgh = 1/2 kx²

k = (2 * 25 * 9.81 * 0.5) / 0.4²

k = 1533 N/m

We will apply

2as = v² - u², with u = 0

a = F/m

F = kx

a = kx/m

v = √ (2 x 0.4 x (0.4 x 1533 / 25))

v = 4.43 m/s