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13 June, 05:12

A railway truck of mass 800 kg moving with a constant velocity of 5 m/s, collides and couples

with another railway truck of mass 6+50 kg

which is stationary. Calculate the common velocity (v) with which the coupled trucks move off

after the collision.

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Answers (1)
  1. 13 June, 05:29
    0
    The common velocity of truck v = 2.759 m/s

    Explanation:

    Given that,

    Mass of first railway truck, M = 800 Kg

    Mass of second railway truck, m = 650 Kg

    Velocity of first railway truck, U = 5 m/s

    Velocity of second truck, u = 0 m/s

    According to the conservation of linear momentum,

    The total momentum after impact = total momentum before impact

    The mass of the truck remains the same, but the velocity after impact is coupled to be v.

    Therefore,

    Mv + mv = MU + mu

    v (M+m) = MU (u = 0)

    v = MU / (M+m)

    Substituting the values in the above equation,

    v = 800 Kg x 5 m/s / (800 Kg + 650 Kg)

    v = 2.759 m/s

    Hence, the common velocity of the coupled tucks moving off after collision is v = 2.759 m/s
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