Ask Question
25 August, 15:09

A large rectangular raft has a density of 725.5 kg/m3) and floating on a lake. The surface area of the top of the raft is 39.6 m 2 and its volume is 5.2 m3. Assume acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. How many meters "h" is the raft above the water?

+5
Answers (1)
  1. 25 August, 15:31
    0
    h=0.036 m

    Explanation:

    First we calculate the volume of the raft:

    Volume of the raft = raft surface x A

    where A is the dimension of the raft that we don't know but we know that A = h+d where d is the submerged edge from the raft and h the distance asked

    Volume of the raft = raft surface x A

    5.2 m3=39.6 m2 x A

    A = (13/99) m

    Now let's calculate de weight of the raft:

    ρ=m/v

    ρ (raft) = m (raft) / v (raft)

    725.5 kg/m3 = m (raft) / 5.2 m3

    m (raft) = 3772.6 kg

    W=m x g

    W (raft) = m (raft) x g

    W = 3772.6 kg x 9.8 m/s2

    W = 36971.48 N

    The raft is floating so W (raft) = water thrust

    Water thrust = water volume x water density x gravity

    36971.48 N = (39.6 m2 x d) x (1000 kg/m3) x 9.8 m/s2

    d = 0.0953 m

    Finally A=h+d

    h = A - d

    h = (13/99) m - 0.0953 m

    h = 0.036 m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A large rectangular raft has a density of 725.5 kg/m3) and floating on a lake. The surface area of the top of the raft is 39.6 m 2 and its ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers