A baseball 0.145kg is thrown vertically upwards with an initial velocity of 20m/s. Use the law of conservation of energy to find how high it goes ignoring air resistance.

Answer: 20.4m

Explanation:

Mass = 0.145kg

Initial velocity, Vi = 20m/s

Initial kinetic energy K = 1/2mv^2

Initial potential energy Ui = mgx = 0joules

: From conservation of energy,

Uf + Kf = Ui + Ki (where f represent (final))

Thus

mgXf + 0 = 0+1/2 mv^2

Xf = Vi^2 / 2g

= (20m/s) ^2 / 2 (9.81m/s) ^2

=20.4m