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14 May, 19:40

Suppose that two identical stars (they have the same total light output) are located so that star A is at a distance of 5 pc and star B is at a distance of 25 pc from Earth. How will star B appear, compared with star A?

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  1. 14 May, 19:53
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    star B will appear 1/25 = 0.04 times compared to star A

    star b will look smaller from star A

    Explanation:

    star A is at a distance of 5 pc

    star B is at a distance of 25 pc

    How will star B appear, compared with star A?

    the inverse square law of light for apparent brigthness, b =

    b = L / (4πd²)

    where, L is the luminiosity = light output

    d = distance

    L₁ / (4πd₁²) = L₂ / (4πd₂²)

    since L, is constant

    d₁² = d₂²

    5² = 25²

    [5/25]² = [1/5]² = 1/25

    star B will appear 1/25 = 0.04 times compared to star A

    star b will look smaller from star A
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