Ask Question
14 May, 09:22

A proton is placed in an electric field of intensity 700 n/

c. what is the magnitude and direction of the acceleration of this proton due to this field?

+5
Answers (1)
  1. 14 May, 09:27
    0
    F=ma

    F=QE = 1.602e-19C*700N/C = 1.1214e-16N

    1.1214e-16N = ma = 1.6726e-27kg * a

    a = 6.702e10 m/s² along the direction of the field line
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A proton is placed in an electric field of intensity 700 n/ c. what is the magnitude and direction of the acceleration of this proton due ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers