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9 April, 11:53

a certain engine has a second-law efficiency of 85%. During each cycle, it absorbs 480J of heat form a reservoir at 300C and dumps 300J of heat to a cold termperature reservoir. What is the temperature of the cold reservoir?

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  1. 9 April, 12:04
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    Tc = 85.95 K

    Explanation:

    Given:

    Th = 300 C = 573 K

    η = 85 % =.85

    Tc=?

    so we have equation for Efficiency

    η = 1 - (Tc/Th)

    ⇒Tc = (1 - η) Th

    Tc = (1 -.85) x 573 K

    Tc = 85.95 K
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