An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m

Question

Mckenzie Wilkerson

Physics

23 April, 17:26

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m

+1

Answers (2)

Know the Answer?

Alan Murillo · Answer 1

C) 1.0 m

Explanation:

The component of the velocity parallel to the sidewalk is:

vₓ = v cos θ

vₓ = 0.1 m/s cos 45°

vₓ = 0.0707 m/s

The distance traveled after 14 seconds is:

d = vₓ t

d = (0.0707 m/s) (14 s)

d = 0.99 m

Closest answer is C) 1.0 m.

Rebecca Maxwell · Answer 2

C) 1.0m

Explanation:

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, it will have traveled 1.0m in the direction parallel to the edge of the sidewalk.

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?A) 0.005mB) 0.01mC) 1.0mD) 9.9m

An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45 degrees relative to the edge of the sidewalk. After 14sec, how far will it have traveled in the direction parallel to the edge of the sidewalk?

A) 0.005m

B) 0.01m

C) 1.0m

D) 9.9m