10.0 gram gas occupies 12.5 liter at pressure of 42.0 mm hg whAt volume when pressure increase 75.0 mm hg

Question

Kymani Mullins

Physics

12 June, 09:37

10.0 gram gas occupies 12.5 liter at pressure of 42.0 mm hg whAt volume when pressure increase 75.0 mm hg

+2

Answers (1)

Know the Answer?

Jazlyn Solis · Answer 1

Oh goodness me, Isn't this Boyle's Law.

That P1V1 = P2V2, V1 = 12.5 liter, P1 = 42 mmHg, P2 = 75 mmHg.

V2 = P1V1/P2.

V2 = (42 * 12.5) / 75 Use your calculator.

V2 = 7 liter.

That's it. Cheers.