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1 February, 18:58

Two engineering students, John with a weight of 92 kg and Mary with a weight of 46 kg, are 30 m apart. Suppose each has a 0.04% imbalance in the amount of positive and negative charge, one student being positive and the other negative. Estimate the electrostatic force of attraction between them by replacing each student with a sphere of water having the same mass as the student. N

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  1. 1 February, 19:03
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    F = 6.27 x 10 ¹⁹ N

    Explanation:

    Given

    m₁ = 92 kg, m₂ = 46 kg, % = 0.04% N = 6.022 x 10²³ Z = 18, e = 1.6 x 10 ⁻¹⁹ C, M = 0.018 kg/mol

    q₁ = % * [m * N * A * e / M ]

    q₁ = 0.0004 * [ (92 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹) / (0.018 kg/mol) ]

    q₁ = 3.54 x 10⁶ C

    q₂ = 0.0004 * [ (46 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹) / (0.018 kg/mol) ]

    q₂ = 1.773 x 10⁶ C

    Now to determine the electrostatic force con use the equation

    F = K * q₁ * q₂ / d²

    K = 8.99 x 10 ⁹

    F = 8.99 x 10 ⁹ * 3.54 x 10⁶ C * 1.773 x 10⁶ C / (30m) ²

    F = 6.27 x 10 ¹⁹ N
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