Ask Question
8 August, 15:24

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

+2
Answers (1)
  1. 8 August, 15:54
    0
    vf^2 = vi^2 + 2*a*d

    ---

    vf = velocity final

    vi = velocity initial

    a = acceleration

    d = distance

    ---

    since the airplane is decelerating to zero, vf = 0

    ---

    0 = 55*55 + 2 * (-2.5) * d

    d = (-55*55) / (2 * (-2.5))

    d = 605 meters
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration. ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers