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7 October, 22:43

Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the amount of impulse given to the wall?

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  1. 7 October, 23:01
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    Mass of the ball is m = 15 kg

    Velocity of the ball is v = 8 m/s

    The momentum of the ball is

    P = mv = (15 kg) * (8 m/s) = 120 (kg-m) / s

    Because the ball rebounds elastically, its rebound velocity is 8 m/s in the opposite direction.

    The change in momentum of the ball is

    2P = 240 (kg-m) / s.

    The impulse on the wall is equivalent to the change in the momentum of the ball, so it is 240 (kg-m) / s

    Answer: 240 (kg-m) / s
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