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14 December, 02:15

A 2-kg block slides along a rough horizontal surface and slows to 10 m/s after traveling 20 m. If the kinetic coefficient of friction between the block and surface is 0.2, the initial speed (m/s) of the block was most nearly:

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  1. 14 December, 02:31
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    initial speed is 13.36 m/s

    Explanation:

    given data

    mass = 2 kg

    velocity = 10 m/s

    distance = 20 m

    friction = 0.2

    to find out

    initial speed

    solution

    we find first friction force that is

    friction force = friction * mass*g ... 1

    put here value

    friction force = 0.2 * 2 * 9.81

    friction force = 3.924 N

    here a will be - ve due to friction

    - friction force = mass * acceleration

    acceleration = - friction force / mass

    acceleration = - 3.924 / 2

    acceleration = - 1.962 m/s²

    and we know velocity formula that is

    V² = V (i) ² + 2as

    put here value

    10² = V (i) ² + 2 (-1.962) (20)

    V (i) = 13.36

    so initial speed is 13.36 m/s
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