If a 60.1 kg person jumps onto a seesaw at an angle of 22 degrees at a distance of 6.9 m from the fulcrum.

How much force will their friend feel if they are sitting 6.6 m on the opposite side of the seesaw?

Question

Luca Marquez

Physics

15 October, 17:33

If a 60.1 kg person jumps onto a seesaw at an angle of 22 degrees at a distance of 6.9 m from the fulcrum.

How much force will their friend feel if they are sitting 6.6 m on the opposite side of the seesaw?

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Answers (1)

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Tripp · Answer 1

On the opposite side of the seesaw, the friend will feel a force of 231.66 N

Explanation:

R₁F (input) sin∅ = R₂F (output)

F (output) = R₁F (input) sin∅ / R₂

= (6.9/6.6) (60.1 * 9.8) Sin 22°

= 1.05 (588.98) Sin22°

= 1.05 * 588.98 * 0.3746

F (output) = 231.66 N

If a 60.1 kg person jumps onto a seesaw at an angle of 22 degrees at a distance of 6.9 m from the fulcrum.How much force will their friend feel if they are sitting 6.6 m on the opposite side of the seesaw?

If a 60.1 kg person jumps onto a seesaw at an angle of 22 degrees at a distance of 6.9 m from the fulcrum.

How much force will their friend feel if they are sitting 6.6 m on the opposite side of the seesaw?