A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 58.5 ∘c. part a what is the mass of the water? express your answer to two significant figures and include the appropriate units.

Question

Aileen Sweeney

Physics

11 November, 09:00

A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 58.5 ∘c. part a what is the mass of the water? express your answer to two significant figures and include the appropriate units.

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Answers (1)

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Mitchell Rollins · Answer 1

The specific heat capacity of iron = 0.450 J/g°C

and the specific heat water = 4.18 J/g°C

Heat gained by iron;

= 33 * 0.450 (58.5-22.7)

= 531.63 J

Heat lost by water; assuming the mass of water m

= m * 4.18 * (63.3 - 58.5)

= 20.064m

But; heat gained = heat lost

20.064 m = 531.63

m = 26.497 g

Therefore, the mass of water is 26.497 g