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28 July, 17:44

You are trying to experimentally determine the electric potential of a conducting sphere, which you know is given by V=kQ/r. You experimentally measured the charge to be Q=3.2042e-19 C and the radius to be r=0.08 m, and also find you have an uncertainty in both of those quantities equal to ΔQ=1.6021e-21 C and Δr=0.005 m respectively. What is the uncertainty in V due to the uncertainty in your measurement of the radius r?

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  1. 28 July, 18:07
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    Uncertainty ΔV = 22.601 x 10^-10

    ΔV = 2.2601nv or 2.2601 x 10^9V

    Explanation:

    from V = kQ/r

    Uncertainty in V is given by δV = V square root [ (δQ/Q) ^2 + (δr/r) ^2]

    ΔV = V square root [ (ΔQ/Q) ^2 + (Δr/r) ^2] ... (2)

    Given that; Q = 3.2042e-19 C, r = 0.08 m, ΔQ = 1.6021e-21 C, Δr = 0.005 m

    Plugging the values given into equation (2)

    from ΔV = (kQ/r) square root [ (ΔQ/Q) ^2 + (Δr/r) ^2]

    ΔV = 9 x 10^9 x 3.2042e-19 / 0.08 square root [ (1.6021e-21 / 3.2042e-19) ^2 + (0.005/0.08) ^2]

    ΔV = 360.47 x 0.06269 x 10^-10

    Uncertainty ΔV = 22.601 x 10^-10

    ΔV = 2.2601nv or 2.2601 x 10^-9V
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