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30 January, 04:11

Our boss asks you compare two sound waves and determine which has the higher frequency. Wave A has a period of 4⁄100 second and Wave B has a perio of 1⁄7 second.

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  1. 30 January, 04:14
    0
    Wave A - period = 4/100 and the frequency = 1 / (4/100) = 100/4 = 25 Hz

    Wave B - period = 1/7 and the frequency = 1 / (1/7) = 7 Hz

    Wave A has a higher frequency.
  2. 30 January, 04:34
    0
    The periodic time is the inverse of frequency. This means that:

    Period = 1/frequency

    Therefore,

    Frequency = 1/period

    For wave A:

    period = 4/100

    frequency = 1 / (4/100) = 100/4 = 25 Hz

    For wave B:

    period = 1/7

    frequency = 1 / (1/7) = 7 Hz

    Based on this, wave A has higher frequency.
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