A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s. what work did the shot-putter do on the ball?

Question

Hayden Baxter

Physics

11 April, 15:33

A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s. what work did the shot-putter do on the ball?

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Starr · Answer 1

1.0x10^3 Joules The kinetic energy a body has is expressed as the equation E = 0.5 M V^2 where E = Energy M = Mass V = Velocity Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion E = 0.5 * 7.2 kg * (17 m/s) ^2 E = 3.6 kg * 289 m^2/s^2 E = 1040.4 kg*m^2/s^2 E = 1040.4 J So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules