Calculate the magnetic field strength needed on a  170-turn square loop  22  cm on a side to create a maximum torque of  295  N·m if the loop is carrying  20  A.

B = 1.823 T.

Explanation:

Given,

Number of turns, N = 170 turn

Side of square loop, L = 22 cm

Maximum torque, τ = 295 N. m

Current on the loop, I = 20 A

Magnetic strength = ?

Torque = N BIA

300 = 170 x B x 20 x 0.22²

300 = 164.56 B

B = 1.823 T.

Hence, the magnetic field strength is equal to B = 1.823 T.