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30 March, 17:07

A bullet of mass m = 10 gram strikes a ballistic pendulum of mass m=2.0 kg. the center of mass of the pendulum rises a vertical distance of h=12 cm. assuming the bullet remains embedded in the pendulum, calculate its initial speed.

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  1. 30 March, 17:08
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    Assumption made: No energy is loss!

    The g is 10N/kg

    Total mass = 0.01kg+2kg = 2.01kg

    Gravitational Potential Energy = 2.01kg * 0.12m * 10N/kg = 2.412J

    Kinetic energy = 2.412J since no energy is lost

    Velocity = ((2.412J * 2) / 2.01kg) ^0.5 = 1.55m/s
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