Ask Question
10 March, 10:31

Water is pumped from a 200-ft-deep well into a 100-ft-high storage tank. Determine the power, in kW, that would be required to pump 310 gal/min. The density of water is taken to be 62.4 lbm/ft3.

+1
Answers (1)
  1. 10 March, 10:54
    0
    height raised, h = 200 + 100 = 300 ft

    Q = 310 gal / min = 310 / 60 = 5.17 gal/sec

    density of water, d = 62.4 lbm/ft^3 = 8.34 lbm/gal

    Power = h d g x Q

    P = h (dg) Q

    P = 300 x 8.34 x 5.17

    P = 12935.34 lbf - ft / s

    P = 23.52 hp
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Water is pumped from a 200-ft-deep well into a 100-ft-high storage tank. Determine the power, in kW, that would be required to pump 310 ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers