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26 December, 20:10

I have a hot air balloon that has 18.0 g helium gas inside of it. if the pressure is 2.00 atm and the temperature is 297k, what is the volume of my balloon?

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Answers (2)
  1. 26 December, 20:14
    0
    M = molar mass of the helium gas = 4.0 g/mol

    m = mass of the gas given = 18.0 g

    n = number of moles of the gas

    number of moles of the gas is given as

    n = m/M

    n = 18.0/4.0

    n = 4.5 moles

    P = pressure = 2.00 atm = 2.00 x 101325 Pa = 202650 Pa

    V = Volume of balloon = ?

    T = temperature = 297 K

    R = universal gas constant = 8.314

    Using the ideal gas equation

    P V = n R T

    (202650) V = (4.5) (8.314) (297)

    V = 0.055 m³
  2. 26 December, 20:25
    0
    The volume of balloon is 54.86 L

    calculation

    The volume is calculated using the ideal gas equation

    That is PV=nRT

    where,

    p = 2.00 atm

    V=?

    n (number of moles) which is calculated as below

    moles = mass / molar mass = 18.0g / 4 g/mol = 4.5 moles

    R (gas constant) = 0.0821 L. atm / mol. K

    T (Temperature) = 297 K

    make V the subject of the formula by diving both side by P

    V = nRT/P

    V = { (4.5 moles x 0.0821 L. atm/mol. K x 297 K) / 2.00 atm} = 54.86 L
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