A particular planet has a moment of inertia of 8.26 * 10^ (36) kg⋅m^2 and a mass of 6.54 * 10^22 kg. Based on these values, what is the planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5) mr^2.

Question

Alice Lambert

Physics

3 February, 05:57

A particular planet has a moment of inertia of 8.26 * 10^ (36) kg⋅m^2 and a mass of 6.54 * 10^22 kg. Based on these values, what is the planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5) mr^2.

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Answers (1)

Know the Answer?

Cindy · Answer 1

Answer: 1.776933x10^7

Explanation:

Moment of inertia I = 8.26x10^36kgm^2

Mass of planet m = 6.54x10^22kg

Also, Planet is solid sphere so that, Moment of inertia is I = _2_ m

R^2 = 0.4 R^2 5

Where R is radius of planet

Putting into calculation

We get,

I = _2_ m R^2

5

8.26x10^36 = 0.4x6.54x10^22xR^2

8.26x10^14 = 2.616 R^2

R = 1.776933x10^7