Ask Question
14 June, 19:32

Boy pulls a 5.0-kg sled with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond. The boy pulls on the rope with a force of 10.0 N; and the sled moves with constant velocity. What is the coefficient of friction between the and the ice?

(a) 0.09

(b) 0.12

(c) 0.18

(d) 0.06

(e) 0.24

+5
Answers (1)
  1. 14 June, 19:54
    0
    0.1

    Explanation:

    mass, m = 5 kg

    θ = 60°

    Force, F = 10 N

    velocity is constant, it means the net force is zero.

    So, the component of force along the surface is equal to the friction force

    FCosθ = friction force

    10 x cos 60 = μ x m x g

    where, μ is the coefficient of friction

    5 = μ x 5 x 9.8

    μ = 0.1

    Thus, the coefficient of friction is 0.1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Boy pulls a 5.0-kg sled with a rope that makes a 60.0° angle with respect to the horizontal surface of a frozen pond. The boy pulls on the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers