A torque of 50 Nm acts on a wheel of moment of inertia 25 kgm^2 for 4 s and then is removed.

b) How many revolutions does it make in 15 s if it starts at rest?

I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.

Question

Lauryn Brandt

Physics

22 May, 09:54

A torque of 50 Nm acts on a wheel of moment of inertia 25 kgm^2 for 4 s and then is removed.

b) How many revolutions does it make in 15 s if it starts at rest?

I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.

+3

Answers (1)

Know the Answer?

Charlie Casey · Answer 1

You have to find the calculate the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each revolution. Then you can multiply by the number of revolutions per minute.

A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.b) How many revolutions does it make in 15 s if it starts at rest?I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.

A torque of 50 Nm acts on a wheel of moment of inertia 25 kgm^2 for 4 s and then is removed.

b) How many revolutions does it make in 15 s if it starts at rest?

I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.