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9 December, 22:30

A person rides a Ferris wheel that turns with constant angular velocity. Her weight is 549.0 N. At the top of the ride her apparent weight is 1.500 N different from her true weight. What is her apparent weight at the top of the ride?

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  1. 9 December, 22:45
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    Given that the angular velocity is constant.

    The actual weight is W = 549N

    The ride apparent weight is

    W' = 1.5N

    Apparent weight at the top of the ride?

    Using newton second law of motion

    ΣF = m•ar

    ar is the radial acceleration

    N - W = - m•ar

    N = W - m•ar

    N = mg - m•ar

    N = m (g-ar)

    The apparent weight is equal to the normal

    W' (top) = N = m (g-ar)

    W' (top) = m (g-ar)

    W' (top) = mg - m•ar

    We know that the actual weight is

    W=mg

    Also, the apparent weight is

    W' = m•ar

    Then

    W' (top) = Actual weight - apparent

    W' (top) = 549-1.5

    W' (top) = 547.5 N
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