The time a basketball player spends in the air when shooting a basket is called the "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4t2. suppose that a basketball player has a vertical leap of 4 feet 4 inches. find the hang time for this leap.

Question

Max Foley

Physics

27 November, 19:48

The time a basketball player spends in the air when shooting a basket is called the "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4t2. suppose that a basketball player has a vertical leap of 4 feet 4 inches. find the hang time for this leap.

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Karley Hammond · Answer 1

I believe that L is in feet while t is in seconds. To find for the hang time, all we have to do is to plug in the value of L in feet in the equation.

4 inches is equivalent to 4/12 feet or 0.33 feet, therefore the total L is:

L = 4.33 ft

Using the equation to find for t:

L = 4 t^2

4.33 = 4 t^2

t = 1.04 s