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21 March, 08:01

A 66-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.90 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.6 s, and then comes to rest. What does the spring scale register in each of the following time intervals?

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  1. 21 March, 08:05
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    Answer:735.46N, 626.34N

    Explanation: when an elevator ascend, it means it moving against gravity

    F = m (a+g)

    M=66kg

    a=v/t

    g=9.81m/s^2

    For the first a = 1.2/0.9

    a=1.2/0.9

    a=1.33m/s2

    F=66 (1.33+9.81)

    F=66 (11.143)

    F=735.46N

    F=m (a+g)

    a=v/t

    a=-1.6/5

    a=-0.32m/s2

    F=66 (-0.32+9.8)

    F=66 (9.49)

    F=626.34N
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