A 1790 kg car has just passed a diner. The closest the car came to the diner was R=28.5 m, but the car has driven another x=42.7 m in the 2.85 s2.85 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?

Question

Lily Esparza

Physics

6 July, 09:38

A 1790 kg car has just passed a diner. The closest the car came to the diner was R=28.5 m, but the car has driven another x=42.7 m in the 2.85 s2.85 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner?

+1

Answers (1)

Know the Answer?

Moran · Answer 1

6208270.4 kg. m^2/s^1

Explanation:

let X = x = 42.7 m and t = 2.85s

the speed of the car, v = X*t

= 42.7*2.85

= 121.695 m/s

then, we know that the angular momentum is given by:

when the is just passing the dinner, the distance from the diner to the car is perpendicular to the cars trajectory.

L = m*R*v, where R is the perpendicular distance.

= 1790*28.5*121.695

= 6208270.4 kg. m^2/s^1