A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.

Find the magnitude of the truck's horizon - tal component of displacement.

Answer in units of m.

The horizontal component of displacement is d' = 1422.7 m

Explanation:

Given data,

The distance covered by the truck, d = 1430 m

The angle formed with the horizontal, Ф = 5.76°

The displacement is a vector quantity.

The horizontal component of displacement is given by,

d' = d cos Ф

= 1430 cos 5.76°

= 1422.7 m

Hence, the horizontal component of displacement is d' = 1422.7 m