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27 June, 22:26

An inductor is connected to an AC power supply having a maximum output voltage of 3.00 V at a frequency of 280 Hz. What inductance is needed to keep the rms current less than 2.50 mA? (Provide the minimum value.)

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  1. 27 June, 22:45
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    L = 0.48 H

    Explanation:

    let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax be the maximum voltage and XL be the be the reactance of the inductor.

    Vrms = Vmax / (√2)

    = (3.00) / (√2)

    = 2.121 V

    then:

    XL = Vrms/I

    = (2.121) / (2.50*10^-3)

    = 848.528 V/A

    that is L = XL / (2*π*f)

    = (848.528) / (2*π * (280))

    = 0.482 H

    Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.
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