If a dam has water 100 m deep behind it, how much energy (in MJ) was generated if 11,200 kg of water exited the dam at 2.4 m/s?

The energy generated = 11008256 J

Explanation:

Energy; This can be defined as the ability or the capacity to do work. The unit of energy is Joules (J).

Energy is divided into two,

(i) potential Energy

(ii) Kinetic Energy.

(i) Potential Energy: This is the energy of a body in position

Ep = mgh ... Equation 1

(ii) Kinetic Energy: This is the energy of a body i n motion

Ek = 1/2mv² ... Equation 2

From the question above,

Using,

Ep = mgh

Where EP = Potential Energy m = mass of the water, h = height of the water, g = acceleration due to gravity.

Given: m = 11200 kg, h = 100 m, Constant g = 9.8 m/s²

Substituting these values into equation (1)

Ep = 11200*100*9.8

Ep = 10976000

Ep = 10.97 MJ

Ek = 1/2mv² ... Equation 2

Given: m = 11200 kg, v = 2.4 m/s

Ek = 1/2 (11200) (2.4) ²

Ek = 32256 J

Energy generated = 10976000 + 32256 = 11008256 J

Thus the the amount of energy generated = 11008256 J