A car starts from rest and accelerates from u seconds until it reaches a speed of 10ms

the car then travels at 10ms for 2u seconds.

the diagram shows the speed time graph for journey.

the distance travlled by the car in the first 3u seconds is 125m

a, find the value of U

b, find the acceleration in the first u seconds?

Question

Emerson Garner

Physics

26 March, 21:03

A car starts from rest and accelerates from u seconds until it reaches a speed of 10ms

the car then travels at 10ms for 2u seconds.

the diagram shows the speed time graph for journey.

the distance travlled by the car in the first 3u seconds is 125m

a, find the value of U

b, find the acceleration in the first u seconds?

+1

Answers (1)

Know the Answer?

Jasmin Callahan · Answer 1

Distance = speed * time

10x10^-3 * u + 10x10^-3 * 2u = 125

0.01u + 0.02u = 125

0.03u = 125

u = 4166.66666 ... s

acceleration = (final velocity - initial velocity) / time

(10x10-3 - 0) / 4167 = 2.3998 * 10^-6 m s-2