A pair of electrically charged objects attract each other with a force of 20 n when they are a distance of 5 m apart. if their charges stay the same, then what will be the attractive force between them when they are 20 m apart?

Assume that the two charges are q1 and q1.

The force of attraction between the two charges is given by the following equation:

F = (k * q1 * q2) / (r^2)

F1 = 20n

r1 = 5m and r2 = 20m

We can notice that r2 = 4r1

therefore,

F2 = (k * q1 * q2) / [ (4r) ^2]

F2 = (1/16) x F1

Since F1 = 20n, therefore,

F2 = (1/16) x 20 = 1.25n