A truck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s. (a) find its original speed. (b) find its acceleration.

Speed equation: speed = total distance/total time

speed = 40.0m / 8.50s

speed = 4.71 m/s

acceleration equation: acceleration = change in velocity/time

4.71 - 2.80 = 1.91 (change in velocity)

acceleration = 1.91/8.50

acceleration =.22 m/s^2

a) 4.71 m/s

b).22 m/s^2