A 1.5 g iron nail is heated to 95.0 °c and placed into a beaker of water. calculate the heat gained by the water if the final equilibrium temperature is 57.8 °

c. the specific heat capacity of iron = 0.449 j / g ° c, and the specific heat capacity of water = 4.18 j / g ° c

Question

Hensley

Physics

8 December, 19:25

A 1.5 g iron nail is heated to 95.0 °c and placed into a beaker of water. calculate the heat gained by the water if the final equilibrium temperature is 57.8 °

c. the specific heat capacity of iron = 0.449 j / g ° c, and the specific heat capacity of water = 4.18 j / g ° c

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Answers (1)

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Virginia Ryan · Answer 1

Heat gained by water = 25.1 J

Explanation:

As per the law of conservation of energy

Heat gained by water = Heat lost by the nail

Heat lost by nail = Q = m c ΔT

m = mass of nail = 1.5 g

c = specific heat capacity of nail=0.449 j / g °C

ΔT = change in temperature=57.8-95 = - 37.2° C

Q=1.5 (0.449) (-37.2)

Q=-25.1 J

This is negative because the heat is lost by the nail. Same amount of heat is gained by the water.

so heat gained by water=25.1 J

A 1.5 g iron nail is heated to 95.0 °c and placed into a beaker of water. calculate the heat gained by the water if the final equilibrium temperature is 57.8 °c. the specific heat capacity of iron = 0.449 j / g ° c, and the specific heat capacity of water = 4.18 j / g ° c

A 1.5 g iron nail is heated to 95.0 °c and placed into a beaker of water. calculate the heat gained by the water if the final equilibrium temperature is 57.8 °

c. the specific heat capacity of iron = 0.449 j / g ° c, and the specific heat capacity of water = 4.18 j / g ° c