Ask Question
30 June, 02:08

A car rolls along a surface with a coefficient of friction of. 795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?

+2
Answers (1)
  1. 30 June, 02:27
    0
    102.5 km/hr = 28.5 m/s

    a = (28.5 - 0) / 10

    a = 2.85 m/s²

    Resultant force = forward force - friction

    ma = F - μmg

    F = ma + μmg

    F = 905 (2.85 + 0.795 x 9.81)

    F = 9637.3 N

    F = 9600 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A car rolls along a surface with a coefficient of friction of. 795 I f the car has a mass of 905 kg, what force is needed to accelerate the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers