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27 May, 13:04

The battery of a flashlight develops 3 V, and the current through the bulb is 200 mA. What power is absorbed by the bulb?

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  1. 27 May, 13:23
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    Answer : The power absorbed by the bulb is, 0.600 W

    Explanation:

    As we know that,

    Power = Voltage * Current

    Given:

    Voltage = 3 V

    Current = 200 mA = 0.200 A

    Conversion used : (1 mA = 0.001 A)

    Now put all the given values in the above formula, we get:

    Power = Voltage * Current

    Power = 3V * 0.200 A

    Power = 0.600 W

    Thus, the power absorbed by the bulb is, 0.600 W
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