A traveling sinusoidal electromagnetic wave in vacuum has an electric field amplitude of 91.1 V/m. Find the intensity of this wave and calculate the energy flowing during 17.1 s through an area of 0.0269 m2 that is perpendicular to the wave/'s direction of propagation.

intensity is 11.0145 W/m^2

Energy is 5.07 J

Explanation:

Given data

amplitude E = 91.1 V/m

area = 0.0269 m2

time t = 17.1 s

to find out

intensity and energy

solution

we know intensity formula that is given below

intensity = E (rms) ² / (cμ0)

here c is speed of light and μo is permeability of free space

we know these constant value c = 2.99 x 10^8

μo = 1.26 x 10^-6

put all these value and we get intensity

intensity = (91.1/√2) ² / (2.99 x 10^8 * 1.26 x 10^-6)

intensity = 4149.605 / 3.7674 x 10^2

intensity is 11.0145 W/m^2

and Energy is calculated by this formula

Energy = intensity * time * area

put all value now here

Energy = 11.0145 * 17.1 * 0.0269

Energy is 5.07 J