A car slows down uniformly from a speed of 29.0 m/s to rest in 8.20 s how far did it travel

For this problem, we use the derived equations for rectilinear motion at constant acceleration.

a = (v - v₀) / t

x = v₀t + 0.5t²

where

a is acceleration

v₀ and v are the initial and final velocities, respectively

x is the distance

t is the time

The solution is as follows:

a = (29 m/s - 0 m/s) / 8.20 s = 3.54 m/s²

Using this to the second equation:

x = (0 m/s) (8.20 s) + 0.5 (3.54 m/s²) (8.20 s) ²

x = 119 m