15 J of work were expended moving an 18 kg block. At what velocity did the block move?

Answer:√ (5/3) m/s

Explanation:

Kinetic energy (ke) = 15j

Mass (m) = 18kg

Velocity (v) = ?

Ke = (mxv^2) / 2

15 = (18xv^2) / 2

Cross product

(18xv^2) = 15x2

18xv^2=30

Divide both sides by 18

(18xv^2) ➗ 18=30 ➗ 18

v^2=5/3

v=√ (5/3)

v=√ (5/3) m/s