A powerful grasshopper launches itself at an angle of 45° above the horizontal and rises to a maximum height of 1.01 m during the leap. With what speed v did it leave the ground? Neglect air resistance. Hint: Use conservation of energy. A. 6.29 m/s B. 7.15 m/s C. 5.98 m/s D. 6.72 m/s E. 5.37 m/s

Question

Devyn Villanueva

Physics

25 August, 21:15

A powerful grasshopper launches itself at an angle of 45° above the horizontal and rises to a maximum height of 1.01 m during the leap. With what speed v did it leave the ground? Neglect air resistance. Hint: Use conservation of energy. A. 6.29 m/s B. 7.15 m/s C. 5.98 m/s D. 6.72 m/s E. 5.37 m/s

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Rylee Nguyen · Answer 1

6.29 m/s option (A)

Explanation:

theta = 45 degree, H = 1.01 m

let v be the launch speed

Use the formula for the maximum height for the projectile

H = v^2 Sin^θ / 2g

1.01 = v^2 x Sin^2 (45) / (2 x 9.8)

1.01 = 0.0255 v^2

v^2 = 39.59

v = 6.29 m/s