Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/s or a 4.0-kilogram ball rolling along the same path at a speed of 1.0 m/s?

its a 8.0 because it heaver

You can do this two ways:

1). Whatever kinetic energy the rolling ball has is the amount

of energy you have to absorb in order to stop it.

2). Whatever momentum the rolling ball has is the amount of

momentum you have to provide in the other direction to cancel it.

Since you asked about force and time, we sense 'impulse' in the

air, and we know that impulse is exactly a change in momentum.

So let's use #2 and talk about momentum and impulse.

Impulse = (force) x (time)

Momentum of a moving object is (mass) x (speed).

- - Momentum of the first ball: (8 kg) x (0.2 m/s) = 1.6 kg-m/s

Impulse required to stop it = 1.6 kg-m/s

(force) x (10 sec) = 1.6

Force required = 1.6 / 10 = 0.16 Newton.

- - Momentum of the second ball: (4 kg) x (1 m/s) = 4 kg-m/s

Impulse required to stop it = 4 kg-m/s

(force) x (10 sec) = 4

Force required = 4 / 10 = 0.4 Newton.

You need more force o stop the second ball. Although its mass

is only 1/2 the mass of the 8kg ball, it's moving 5 times as fast,

and has 2.5 times the momentum of the bigger ball.

So you need 2.5 times as much impulse to stop it.

If you're going to push on each ball for the same length of time,

then you need to push 2.5 times as hard on the smaller ball in

order to stop it.