Ask Question
3 January, 16:56

An archer shoots an arrow at a 75.0 m distant target; the bullâs-eye of the target is at same height as the release height of the arrow. (a) at what angle must the arrow be released to hit the bullâs-eye if its initial speed is 35.0 m/s? in this part of the problem, explicitly show how you follow the steps involved in solving projectile motion problems. (b) there is a large tree halfway between the archer and the target with an overhanging horizontal branch 3.50 m above the release height of the arrow. will the arrow go over or under the branch?

+1
Answers (1)
  1. 3 January, 17:05
    0
    Over the branch with the force of the arrow
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An archer shoots an arrow at a 75.0 m distant target; the bullâs-eye of the target is at same height as the release height of the arrow. ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers