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13 December, 21:34

2. A pebble is dropped down a well and hits the water 1.5 s later. Using the equations for motion with constant acceleration, determine the distance from the edge of the well to the water's surface.

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  1. 13 December, 21:56
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    S = 11.025 m

    Explanation:

    Given,

    The time taken by the pebble to hit the water surface is, t = 1.5 s

    Acceleration due to gravity, g = 9.8 m/s²

    Using the II equations of motion

    S = ut + 1/2 gt²

    Here u is the initial velocity of the pebble. Since it is free-fall, the initial velocity

    u = 0

    Therefore, the equation becomes

    S = 1/2 gt²

    Substituting the given values in the above equation

    S = 0.5 x 9.8 x 1.5²

    = 11.025 m

    Hence, the distance from the edge of the well to the water's surface is, S = 11.025 m
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